Circular Motion questions with solutions

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• MCQeasyCircular MotionFriction in Circular Motion

  A coin rests without slipping on a horizontal disc rotating with constant angular speed. The direction of static friction on the coin is:

  Options

  • Option A

    Tangentially in the direction of motion

  • Option B

    Tangentially opposite to the direction of motion

  • Option C

    Radially inward

  • Option D

    Radially outward

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• MCQmediumCircular MotionCentripetal & Centrifugal Forces

  A stone of mass 0.25 kg tied to the end of a string is whirled round in a circle of radius 1.5 m with a speed of 40 rev/min in a horizontal plane. What is the tension in the string? What is the maximum speed with which the stone can be whirled around if the string can withstand a maximum tension of 200 N ?

  Options

  • Option A

    T≈6.6 N and v(max)≈35 m/s

  • Option B

    T≈13.2 N and v(max)≈20 m/s

  • Option C

    T≈6.6 N and v(max)≈20 m/s

  • Option D

    T≈20 N and v(max)≈35 m/s

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• MCQmediumCircular MotionKinematics of Circular Motion

  A particle moves in a circle of radius 1 m with initial angular speed 12 rad/s. From t=0 it has constant angular acceleration α, and after 2 s its speed becomes (480/π) rpm. It then continues with this attained speed. Determine: (i) α; (ii) tangential speed v(t); (iii) acceleration magnitudes at t=0.5 s and t=3 s; (iv) angular displacement at t=3 s.

  Options

  • Option A

    (i) α=2 rad/s²; (ii) v=12+2t for t≤2 s and 16 m/s for t≥2 s; (iii) a(0.5)=169.01 m/s², a(3)=256 m/s²; (iv) θ(3)=44 rad

  • Option B

    (i) α=4 rad/s²; (ii) v=12+4t; (iii) 196 m/s² and 256 m/s²; (iv) 48 rad

  • Option C

    (i) α=2 rad/s²; (ii) v=12+t; (iii) 144 m/s² and 196 m/s²; (iv) 40 rad

  • Option D

    (i) α=1 rad/s²; (ii) v=12+t; (iii) 156 m/s² and 225 m/s²; (iv) 42 rad

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• MCQmediumCircular MotionKinematics of Circular Motion

  A particle is moving along a circular path of radius 5 m with a uniform speed 5 m s⁻¹. What is the magnitude of average acceleration during the interval in which particle completes half revolution?

  Options

  • Option A

    10/π m/s²

  • Option B

    5/π m/s²

  • Option C

    10/π² m/s²

  • Option D

    5 m/s²

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• MCQeasyCircular MotionCentripetal & Centrifugal Forces

  A man carrying a monkey on his shoulder does cycling smoothly on a circular track of radius 9m and completes 120 revolutions in 3 minutes. The magnitude of centripetal acceleration of monkey is (in m/s²) :

  Options

  • Option A

    zero

  • Option B

    16π² m/s²

  • Option C

    4π² m/s²

  • Option D

    57600π² m/s²

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• MCQmediumCircular MotionFriction in Circular Motion

  A car moving at a speed of 36 km/hr is taking a turn on a circular road of radius 50m. A small wooden plate is kept on the seat with its plane perpendicular to the radius of the circular road in figure. A small block of mass 100g is kept on the seat which rests against the plate. The friction coefficient between the block and the plate is µ = 0.58. (a) Find the normal contact force exerted by the plate on the block. (b) The plate is slowly turned so that the angle between the normal to the plate and the radius of the road slowly increases. Find the angle at which the block will just start sliding on the plate.

  

  Options

  • Option A

    Normal force=0.2 N; limiting angle=30°

  • Option B

    Normal force=1.0 N; limiting angle=60°

  • Option C

    Normal force=0.58 N; limiting angle=45°

  • Option D

    Normal force=0.1 N; limiting angle=30°

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• MCQmediumCircular MotionKinematics of Circular Motion

  A particle starts from rest and moves on a circle of radius R with constant tangential acceleration a₀. Its radial acceleration after time t is:

  Options

  • Option A

    a₀²t²/R

  • Option B

    a₀t

  • Option C

    a₀t²/R

  • Option D

    a₀²t/R

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• NumericmediumCircular MotionFriction in Circular Motion

  A 1 kg coin is placed 0.5 m from the centre of a horizontal disc. At an instant the disc has angular speed 2 rad/s and angular acceleration 4 rad/s². If the required frictional force is N√2 newton, find N.

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• A/RmediumCircular MotionFriction in Circular Motion

  Evaluate the following statements.

  Assertion

  Assertion (A): On a properly banked road, a vehicle can negotiate a circular turn at one particular speed without the help of friction.

  Reason

  Reason (R): At that speed, the horizontal component of the normal reaction provides the required centripetal force while its vertical component balances the weight.

  Options

  • Option A

    Both A and R are true and R is the correct explanation of A.

  • Option B

    Both A and R are true but R is NOT the correct explanation of A.

  • Option C

    A is true but R is false.

  • Option D

    A is false but R is true.

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• MCQmediumCircular MotionFriction in Circular Motion

  A 1000 kg car takes a frictionless banked circular curve of radius 90 m and banking angle 45°. Find speed using g=10 m s⁻².

  Options

  • Option A

    20 m s⁻¹

  • Option B

    30 m s⁻¹

  • Option C

    5 m s⁻¹

  • Option D

    10 m s⁻¹

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