Electrostatic Self-Energy & Equipotential Surfaces questions with solutions

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• ParagraphmediumElectrostaticElectrostatic Self-Energy & Equipotential Surfaces

  Two points charges -Q and +Q√3 are placed in the xy-plane at the origin (0, 0) and a point (2,0), respectively, as shown in the figure. This results in an equipotential circle of radius R and potential V = 0 in the xy-plane with its center at (b, 0). All lengths are measured in meters.

  

  Sub-question 1

  The value of R is meter.

  Your answer

  Sub-question 2

  The value of b is meter.

  Your answer

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  JEE Advanced 2021

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• MCQmediumElectrostaticElectrostatic Self-Energy & Equipotential Surfaces

  1. The figure shows two equipotential lines in the xy-plane. The x-component Eₓ and y-component Eᵧ of the electric field in the region between these equipotential lines are, respectively:

     

  Options

  • Option A

    +100 V m⁻¹, -200 V m⁻¹

  • Option B

    -100 V m⁻¹, +200 V m⁻¹

  • Option C

    +200 V m⁻¹, +100 V m⁻¹

  • Option D

    -200 V m⁻¹, -100 V m⁻¹

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  JEE MainsAdvanced

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• MCQmediumElectrostaticElectrostatic Self-Energy & Equipotential Surfaces

  Some equipotential surfaces are shown in figure. What can you say about the magnitude and the direction of the electric field?

  

  Options

  • Option A

    (a) 200 V m⁻¹ at 120° to the x-axis; (b) radially outward, E = 6/r² V m⁻¹

  • Option B

    Same values with the two cases interchanged

  • Option C

    Half of each stated value

  • Option D

    None of these

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• MCQmediumElectrostaticElectrostatic Self-Energy & Equipotential Surfaces

  Which of the following represents the equipotential lines of a dipole (two equal and opposite charges placed at small separation)?

  Options

  • Option A

    
  • Option B

    
  • Option C

    
  • Option D

    

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• MCQmediumElectrostaticElectrostatic Self-Energy & Equipotential Surfaces

  Figure shows a charge configuration with its equipotential surfaces and electric field lines placed in x-y plane. Mark INCORRECT statement :-

  

  Options

  • Option A

    Potential gradient is positive along $\left(\vec{CD}\right)$

  • Option B

    Potential gradient is negative along $\vec{\left(EF\right)}$

  • Option C

    If a positive charge particle is constrained to move along line AB, it will have constant potential energy.

  • Option D

    A positive charge particle released from rest at C will begin to move in direction $\vec{\left(DC\right)}$

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• MCQmediumElectrostaticElectrostatic Self-Energy & Equipotential Surfaces

  The electric field is $\vec{E}$ = √3$\hat{i}$ - $\hat{j}$ V m⁻¹ at every point in space. Which diagram correctly represents the equipotential lines in the xy-plane?

  Options

  • Option A

    
  • Option B

    
  • Option C

    
  • Option D

    

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• MCQmediumElectrostaticElectrostatic Self-Energy & Equipotential Surfaces

  Eight identical isolated conducting drops, each of radius r and charge q, are initially very far apart. They coalesce into one spherical conducting drop. The ratio of final to initial electrostatic self-energy is:

  Options

  • Option A

    1

  • Option B

    2

  • Option C

    4

  • Option D

    8

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• MCQmediumElectrostaticElectrostatic Self-Energy & Equipotential Surfaces

  Equipotential at a great distance from a collection of charges whose total sum is not zero are approximately

  Options

  • Option A

    spheres

  • Option B

    planes

  • Option C

    paraboloids

  • Option D

    ellipsoids

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• MCQeasyElectrostaticElectrostatic Self-Energy & Equipotential Surfaces

  Some charge is being given to a conductor. Then, its potential:

  Options

  • Option A

    is maximum at surface

  • Option B

    is maximum at centre

  • Option C

    is same throughout the conductor

  • Option D

    is maximum somewhere between surface and centre

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  AIPMT 2002NEET Previous Year

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• MCQmediumElectrostaticElectrostatic Self-Energy & Equipotential Surfaces

  Three concentric spherical shells have radii a, b and c (a < b < c) and have surface charge densities σ, -σ and σ, respectively. If Vₐ, Vᵦ and V𝒸 denote potentials of respective shells, the correct relation is: [Diagram: Image]

  Options

  • Option A

    V𝒸 > Vₐ > Vᵦ

  • Option B

    V𝒸 = Vₐ > Vᵦ

  • Option C

    V𝒸 < Vᵦ < Vₐ

  • Option D

    V𝒸 = Vᵦ = Vₐ

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  AIPMT Screening 2009NEET Previous Year

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