sattelite and keplers law questions with solutions

Showing 1–10 of 33 questions

• MCQeasyGravitationsattelite and keplers law

  A satellite in a circular orbit receives a tangential impulse so that its speed becomes √2 times the circular speed. Its subsequent path is:

  Options

  • Option A

    Elliptical

  • Option B

    Parabolic

  • Option C

    Hyperbolic

  • Option D

    A larger circular orbit

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• MCQmediumGravitationsattelite and keplers law

  Correct formula for height of a satellite from earth's surface is:

  Options

  • Option A

    [(T²R²g)/(4π²)]¹ᐟ² - R

  • Option B

    [(T²R²g)/(4π²)]¹ᐟ³ - R

  • Option C

    [(T²R²)/(4π²g)]¹ᐟ³ - R

  • Option D

    [(T²R²)/(4π²)]¹ᐟ³ + R

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• IntegermediumGravitationsattelite and keplers law

  A satellite of mass m moves in a circular orbit at height R above Earth's surface. Earth has mass M and radius R. If the satellite's angular momentum is m√(NGMR), find N.

  Your answer

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• MCQmediumGravitationsattelite and keplers law

  A satellite moves in a circular orbit of radius r with speed v. Its speed is suddenly reduced to v/√2 without changing direction. Immediately after this change, it is:

  Options

  • Option A

    In a new circular orbit

  • Option B

    At the apogee of an elliptical orbit

  • Option C

    At the perigee of an elliptical orbit

  • Option D

    On a parabolic trajectory

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• MCQmediumGravitationsattelite and keplers law

  A satellite of 10³ kg mass is revolving in circular orbit of radius 2R. If (10⁴R/6) J energy is supplied to the satellite, it would revolve in a new circular orbit of radius : (use g = 10 m/s², R = radius of earth)

  Options

  • Option A

    2.5 R

  • Option B

    3 R

  • Option C

    4 R

  • Option D

    6 R

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  JEE Mains 2024 09 Apr Evening Shift

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• Multi-correctmediumGravitationsattelite and keplers law

  A satellite moves in an elliptical orbit. Let $r_p,$ $v_p$ be perigee distance and speed and $r_a,$ $v_a$ be apogee values. Which statements are correct?

  Select all that apply

  • Option A

    $r_pv_p=r_av_a$

  • Option B

    $v_p>v_a$

  • Option C

    Kinetic energy is maximum at perigee

  • Option D

    Total mechanical energy is larger at perigee than at apogee

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• MCQmediumGravitationsattelite and keplers law

  An astronaut takes a ball of mass m from earth to space. He throws the ball into a circular orbit about earth at an altitude of 318.5 km. From earth's surface to the orbit, the change in total mechanical energy of the ball is xG Mₑm/(21Rₑ). The value of x is: (take Rₑ = 6370 km)

  Options

  • Option A

    11

  • Option B

    9

  • Option C

    12

  • Option D

    10

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• MCQmediumGravitationsattelite and keplers law

  If the distance of the earth from Sun is 1.5 × 10⁶ km. Then the distance of an imaginary planet from Sun, if its period of revolution is 2.83 years is:

  Options

  • Option A

    6 × 10⁷ km

  • Option B

    6 × 10⁶ km

  • Option C

    3 × 10⁶ km

  • Option D

    3 × 10⁷ km

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  JEE Mains24 January 2023Shift 2Evening Shift

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• MCQmediumGravitationsattelite and keplers law

  A spacecraft is in a circular orbit close to Earth's surface. The additional speed required to escape Earth's gravity is, for g = 10 m s⁻² and R = 6400 km:

  Options

  • Option A

    7.9(√2-1) km s⁻¹

  • Option B

    7.4(√2-1) km s⁻¹

  • Option C

    11.2(√2-1) km s⁻¹

  • Option D

    8(√2-1) km s⁻¹

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  JEE Mains11 April 2023Shift 2Evening Shift

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• MCQmediumGravitationsattelite and keplers law

  Assertion (A): The radius vector from the Sun to a planet sweeps out equal areas in equal intervals of time, so the planet's areal velocity is constant. Reason (R): In a central-force field, angular momentum is conserved. Choose the correct answer.

  Options

  • Option A

    Both A and R are correct and R is the correct explanation of A

  • Option B

    Both A and R are correct but R is not the correct explanation of A

  • Option C

    A is correct but R is false

  • Option D

    A is false but R is correct

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