Kinematics part-2 Projectile Motion Physics Questions with Solutions

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MCQmediumKinematics part-2 Projectile Motion
A particle is projected horizontally with speed u from a point at height h above the foot O. An inclined plane through O makes angle α above the horizontal.If x is the horizontal coordinate of the point where the projectile strikes the plane, then x satisfies:
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MCQdifficultKinematics part-2 Projectile Motion
A particle is projected from the top of a tower with speed u at an angle θ above the horizontal, where 0<θ<45°. At some instant its velocity becomes perpendicular to its initial velocity. The vertical displacement y of the particle from the point of projection at that instant is:
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MCQmediumKinematics part-2 Projectile Motion
A projectile is launched from the top of a tower with speed u at an angle θ above the horizontal. It crosses the horizontal level of the point of projection again after time t₁ and strikes the ground after time t₂. If t₂ = 2t₁, and H is the maximum height reached above the point of projection, then the tower height h satisfies:
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MCQmediumKinematics part-2 Projectile Motion
An aeroplane moving horizontally with a speed of 720 km/h drops a food packet, while flying at a height of 396.9 m. The time taken by a food packet to reach the ground and its horizontal range is (Take g = 9.8 m/sec²)
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MCQmediumKinematics part-2 Projectile Motion
A particle is projected horizontally from the top of a tower with speed 10 m/s. Neglect air resistance and take g = 10 m/s². At the instant its velocity makes an angle 60° below the horizontal, its vertical displacement below the point of projection is:
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IntegereasyKinematics part-2 Projectile Motion
A projectile is fired horizontally with a velocity of 98 m/s from the top of a hill 490 m high. Find the time taken to reach the ground. (take g = 9.8 m/s²)
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IntegereasyKinematics part-2 Projectile Motion
A ball is dropped from rest from a height of 18 m above the ground. Taking g = 10 m·s⁻² and neglecting air resistance, at what height above the ground is the numerical magnitude of the velocity equal to the numerical magnitude of the acceleration? Give the answer in metres.
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NumericmediumKinematics part-2 Projectile Motion
A vertical pole has a black mark at some height. A stone is projected from a fixed point on the ground. When projected at an angle 45° it hits the pole orthogonally 1 m above the mark. When projected with a different speed at an angle tan⁻¹( $\frac{3}{4}$ ), it hits the pole orthogonally 1.5 m below the mark. Find the required speed of projection (m/s) so that it hits the mark orthogonally to the pole. Take g = 10 m/s².
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MCQdifficultKinematics part-2 Projectile Motion
From the top of a tower of height h, two particles are projected with the same speed u. One is projected at angle +θ and the other at angle -θ with the horizontal.if their horizontal ranges on the ground are R₊ and R₋, then R₊R₋ equals:
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MCQeasyKinematics part-2 Projectile Motion
An aeroplane is flying in horizontal direction with a velocity 600 km/hr and at a height 1960 m. When it is vertically above the point A, on the ground, a body is dropped from it. The body strikes the ground at point B. The distance AB equal to
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Projectile from height questions with solutions