Pseudo force related problem questions with solutions

Showing 1–3 of 3 questions

• MCQeasyNewtons law of motion and FrictionPseudo force related problem

  Given below are two statements : Statement-I : An elevator can go up or down with uniform speed when its weight is balanced with the tension of its cable. Statement-II : Force exerted by the floor of an elevator on the foot of a person standing on it is more than his/her weight when the elevator goes down with increasing speed. In the light of the above statements, choose the correct answer from the options given below :

  Options

  • Option A

    Both statement I and statement II are false

  • Option B

    Statement I is true but Statement II is false

  • Option C

    Both Statement I and Statement II are true

  • Option D

    Statement I is false but Statement II is true

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  JEE Mains24 January 2023Shift 1Morning Shift

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• MCQmediumNewtons law of motion and FrictionPseudo force related problem

  A small block of mass m slides down from the top of a frictionless inclined surface, while the inclined plane is moving towards left with constant acceleration a₀. The angle between the inclined plane and ground is θ and its base length is L. Assuming that initially the small block is at the top of the inclined plane, the time it takes to reach the lowest point of the inclined plane is ________.

  

  Options

  • Option A

    √[2L/{g sin(2θ) - a₀(1 + cos(2θ))}]

  • Option B

    √[4L/{g sin(2θ) - a₀(1 + cos(2θ))}]

  • Option C

    √[4L/{g cos²θ - a₀ sinθ cosθ}]

  • Option D

    √[2L/{g sinθ - a₀ cosθ}]

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  JEE Mains 202628 January Evening Shift

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• MCQmediumNewtons law of motion and FrictionPseudo force related problem

  A wedge of mass 10 kg rests on a frictionless horizontal surface. Its smooth inclined face makes an angle of 37° with the horizontal. A 2 kg block is placed at the highest point of the incline and is initially at rest relative to the wedge. At t = 0, a constant horizontal force of 24 N is applied to the wedge toward the right. Taking tan37° = 3/4 and g = 10 m·s⁻², approximately how much time does the block take to slide 8.8 m down the incline relative to the wedge?

  

  Options

  • Option A

    2 s

  • Option B

    4 s

  • Option C

    √2 s

  • Option D

    2√2 s

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  JEE Mains 2026 5 April Morning Shift

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