Simple Harmonic Motion questions with solutions

Showing 1–10 of 378 questions

• MCQmediumSimple Harmonic Motion

  Speed v of a particle moving along a straight line, when it is at a distance x from a fixed point on the line, is given by v² = 108 - 9x² (all quantities in SI units). Then

  Options

  • Option A

    The motion is uniformly accelerated along the straight line

  • Option B

    The magnitude of acceleration at a distance 3 cm from the fixed point is 0.27 m s⁻²

  • Option C

    The motion is simple harmonic about x = √12 m

  • Option D

    The maximum displacement from the fixed point is 4 cm

  Check answerShow answer

  JEE MainsAdvanced

  Open question & full solution →
• MCQmediumSimple Harmonic MotionTime Period of Linear Simple Harmonic Motion

  The time period of mass suspended from a spring is T. If the spring is cut into four equal parts and the same mass is suspended from one part, the new time period will be:

  Options

  • Option A

    T/4

  • Option B

    T

  • Option C

    T/2

  • Option D

    2T

  Check answerShow answer

  AIPMT 2003NEET Previous Year

  Open question & full solution →
• MCQmediumSimple Harmonic MotionTime Period of Linear Simple Harmonic Motion

  A uniform solid sphere of mass M and radius R rolls without slipping. A horizontal spring of force constant k is attached to the material point that is uppermost in the equilibrium position. For sufficiently small oscillations, the spring extension may be taken as twice the displacement x of the centre. What is the angular frequency?

  Options

  • Option A

    √[5k/(7M)]

  • Option B

    √[10k/(7M)]

  • Option C

    √[20k/(7M)]

  • Option D

    2√(k/M)

  Check answerShow answer

  JEE MainsNEETJEE Advanced

  Open question & full solution →
• MCQmediumSimple Harmonic MotionTime Period of Linear Simple Harmonic Motion

  A body of mass m is attached to the lower end of a spring whose other end is fixed. The spring has negligible mass. When the mass m is slightly pulled down and released, it oscillates with a time period of 3 s. When mass m is increased by 1 kg, the time period becomes 5 s. The value of m in kg is:

  Options

  • Option A

    $\frac{3}{4}$

  • Option B

    4/3

  • Option C

    16/9

  • Option D

    9/16

  Check answerShow answer

  NEET Phase-II 2016NEET Previous Year

  Open question & full solution →
• NumericmediumSimple Harmonic Motion

  For the shown spring–mass system, if the period of small oscillations about mean position is π√(nm/K), find n. Assume ideal conditions. K₁=2K and K₂=K.

  

  Your answer

  Check answerShow answer

  JEE MainsAdvanced

  Open question & full solution →
• IntegereasySimple Harmonic MotionTime Period of Linear Simple Harmonic Motion

  A particle executes simple harmonic motion along the x-axis and satisfies v² = 50-x², where x is displacement and v is speed in consistent SI units. If the time period of the motion is X / 7 seconds, find X to the nearest integer.

  Your answer

  Check answerShow answer

  JEE Mains 2026 4 April Morning Shift

  Open question & full solution →
• Multi-correctmediumSimple Harmonic MotionDisplacement, Velocity, Acceleration and Phasor Representation in SHM

  Two particles execute SHM on the same line according to x₁ = A sinωt and x₂ = A cosωt. Which statements are correct?

  Select all that apply

  • Option A

    Their first meeting after t = 0 occurs at T/8.

  • Option B

    Their maximum separation is √2A.

  • Option C

    Their velocities first become equal at 3T/8.

  • Option D

    Their speeds are equal at T/8 while their velocities are opposite.

  Check answerShow answer

  JEE MainsNEETJEE Advanced

  Open question & full solution →
• MCQeasySimple Harmonic MotionKinetic Energy, Potential Energy and Conservation of Energy in SHM

  A particle executes SHM with amplitude A. The distance from the mean position when its kinetic energy equals its potential energy is:

  Options

  • Option A

    √2A

  • Option B

    A/2

  • Option C

    A/√2

  • Option D

    2A

  Check answerShow answer

  13 April 2023 Evening Shift

  Open question & full solution →
• IntegermediumSimple Harmonic MotionKinetic Energy, Potential Energy and Conservation of Energy in SHM

  At an instant, an SHM oscillator has displacement y = A cos30°. The amplitude is 40 cm and kinetic energy is 200 J. If the spring constant is 1.0 × 10ˣ N m⁻¹, find x.

  Your answer

  Check answerShow answer

  JEE Mains13 April 2023Shift 1Morning Shift

  Open question & full solution →
• MCQmediumSimple Harmonic Motion

  A plank with a small block on top of it undergoes vertical SHM. Its period is 2 s. The minimum amplitude at which the block will separate from the plank is:

  Options

  • Option A

    10/π²

  • Option B

    π²/10

  • Option C

    20/π²

  • Option D

    π/10

  Check answerShow answer

  JEE MainsAdvanced

  Open question & full solution →