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Physical Pendulum, Torsional Pendulum and Superposition of SHM questions with solutions
Practice Simple Harmonic Motion for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.
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- MCQmediumSimple Harmonic Motion
A particle is subjected to two simple harmonic motions: x₁ = √7 sin(5t) cm and x₂ = 2√7 sin(5t + π/3) cm. The maximum acceleration is x×10⁻² m s⁻². The value of x is:
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JEE Mains 2025 2 April Morning Shift
Open question & full solution → - MCQmediumSimple Harmonic Motion
A uniform disc of mass M and radius R can oscillate in its own plane about a fixed horizontal axis passing through a point A on its rim, as shown in the figure. For small angular oscillations under gravity, what is its time period?

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JEE Mains 2026 4 April Evening Shift
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The composition of two simple harmonic motions of equal periods at right angle to each other and with a phase difference of π results in the displacement of the particles along:
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AIPMT 1990NEET Previous Year
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When two displacements represented by y₁ = a sin(ωt) and y₂ = b cos(ωt) are superimposed, the motion is:
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AIPMT Cancelled 2015NEET Previous Year
Open question & full solution → - MCQmediumSimple Harmonic Motion
A uniform thin rod of length L and mass M is used as a physical pendulum. It is pivoted about a horizontal axis perpendicular to the rod at a point located a distance a from its centre of mass. The rod is given a small angular displacement in a vertical plane and released. What is the time period of small oscillations?
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JEE MainsNEETJEE Advanced
Open question & full solution → - NumericmediumSimple Harmonic Motion
A tank contains two immiscible liquids of densities 6ρ and 2ρ. The higher density liquid is filled up to a height L/2 from the bottom. A thin rod of density ρ and length L is fully immersed and hinged at the bottom so that it can oscillate freely, as shown in the figure. If the rod is slightly disturbed from its equilibrium, the time period of small oscillations is (2π/n)√(L/g), where g is the acceleration due to gravity. The value of n is:

JEE Advanced2026Paper 1
Open question & full solution → - MCQmediumSimple Harmonic Motion
A uniform rod of length L is used as a physical pendulum. Its pivot can be chosen at any point on the rod at distance a from the centre. For small oscillations, at what value of a is the time period minimum?
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JEE MainsNEETJEE Advanced
Open question & full solution → - NumericmediumSimple Harmonic Motion
Two point-like objects of masses 20 gm and 30 gm are fixed at the two ends of a rigid massless rod of length 10 cm. This system is suspended vertically from a rigid ceiling using a thin wire attached to its center of mass, as shown in the figure. The resulting torsional pendulum undergoes small oscillations. The torsional constant of the wire is 1.2 × 10⁻⁸ N m rad⁻¹. The angular frequency of the oscillations is n × 10⁻³ rad s⁻¹. The value of n is [enter value].

JEE Advanced 2023
Open question & full solution → - NumericmediumSimple Harmonic Motion
A thin ring of radius 0.50 m is suspended from a point on its circumference and oscillates in its own vertical plane. Take g = 10 m/s². If ω² = N s⁻², find N.
JEE MainsNEETJEE Advanced
Open question & full solution → - MCQmediumSimple Harmonic Motion
Two simple harmonic motions x = a sin(ωt + δ) and y = a sin(ωt + δ + π/2) act on a particle simultaneously. The motion of the particle will be:
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AIPMT 2000NEET Previous Year
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