Free physics question bank
Thermodynamic Cycles, Heat Engines, Efficiency and Second Law of Thermodynamics questions with solutions
Practice Thermodynamics for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.
Showing 1–10 of 19 questions
- MCQmediumThermodynamics
The heat absorbed by a system in going through the given cyclic process is:
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JEE Mains 2024 05 Apr Morning Shift
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A thermodynamic system undergoes cyclic process ABCDA as shown in the P–V figure. The work done by the system over one full cycle is:
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AIPMT 2014NEET Previous Year
Open question & full solution → - A/ReasyThermodynamics
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion
Efficiency of a reversible heat engine will be highest at -273°C temperature of cold reservoir.
Reason
The efficiency of Carnot’s engine depends not only on the temperature of cold reservoir but also on the temperature of hot reservoir and is given by η = 1 - T₂/T₁.
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JEE Mains30 January 2023Shift 2Evening Shift
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A thermodynamic system is taken through the rectangular cycle ABCDA shown in the P–V diagram, The net heat rejected by the gas during the cycle is:
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AIPMT 2012NEET Previous Year
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Two moles of an ideal gas are taken through the cyclic process abcda shown in a U–V diagram. During processes ab and cd, temperatures are 500 K and 300 K respectively. The volumes at a and d are V₀, and at b and c are 2V₀. Calculate the net heat absorbed by the system. (ln 2 = 0.69 and R = 8.3 J mol⁻¹ K⁻¹)
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AIPMT 2008NEET Previous Year
Open question & full solution → - MCQmediumThermodynamics
A gas is taken through the cycle A → B → C → A as shown in the P–V graph. What is the net work done by the gas?
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NEET 2013NEET Previous Year
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η₁, η₂ and η₃ are efficiencies of Carnot engines operating respectively between 473 K–273 K, 473 K–373 K and 373 K–273 K. Choose the correct relation.
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JEE Mains 2025 28 Jan Morning Shift
Open question & full solution → - MCQeasyThermodynamics
Work done by a Carnot engine operating between temperatures 127°C and 27°C is 2 kJ. The amount of heat transferred to the engine by the reservoir is:
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JEE Mains8 April 2023Shift 2Evening Shift
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A Carnot engine with efficiency 50% takes heat from a source at 600 K. In order to increase the efficiency to 70%, keeping the temperature of sink same, the new temperature of the source will be:
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JEE Mains25 January 2023Morning Shift
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A Carnot engine operates between two reservoirs with efficiency 1/3. When the temperature of the cold reservoir is raised by x, its efficiency decreases to 1/6. If the hot-reservoir temperature is 99°C, x is:
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JEE MainsJEE Advanced
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