Thermodynamic Processes, P-V Diagrams and Work Done questions with solutions

Showing 1–10 of 74 questions

• MCQmediumThermodynamicsThermodynamic Processes, P-V Diagrams and Work Done

  A monoatomic ideal gas initially has pressure P and volume V. It expands adiabatically until its volume becomes 27V. What is the change in internal energy of the gas?

  Options

  • Option A

    -2PV(3√3-1)

  • Option B

    4PV ÷ 3

  • Option C

    -4PV ÷ 3

  • Option D

    3PV ÷ 4

  Check answerShow answer

  JEE Mains 2026 8 April Evening Shift

  Open question & full solution →
• MCQmediumThermodynamicsThermodynamic Processes, P-V Diagrams and Work Done

  Identify the characteristics of an adiabatic process in a monatomic gas. (A) Internal energy is constant. (B) Work done in the process is equal to the change in internal energy. (C) The product of temperature and volume is constant. (D) The product of pressure and volume is constant. (E) The work done to change the temperature from T₁ to T₂ is proportional to (T₂ - T₁). Choose the correct answer.

  Options

  • Option A

    B, E only

  • Option B

    B, D only

  • Option C

    A, C, E only

  • Option D

    A, C, D only

  Check answerShow answer

  JEE Mains 2025 2 April Evening Shift

  Open question & full solution →
• MCQmediumThermodynamicsThermodynamic Processes, P-V Diagrams and Work Done

  A gas is enclosed in a thermally insulating container. Initially its volume is 800 cm³ and temperature is 27°C. It is adiabatically compressed to 200 cm³. Take γ = 1.5. The change in temperature is:

  Options

  • Option A

    327 K

  • Option B

    300 K

  • Option C

    600 K

  • Option D

    522 K

  Check answerShow answer

  JEE Mains 2025 3 April Morning Shift

  Open question & full solution →
• MCQmediumThermodynamicsThermodynamic Processes, P-V Diagrams and Work Done

  Match List-I with List-II. List-I: (A) Triatomic rigid gas, (B) Diatomic non-rigid gas, (C) Monoatomic gas, (D) Diatomic rigid gas. List-II: (I) Cp/Cv = 5/3, (II) Cp/Cv = 7/5, (III) Cp/Cv = 4/3, (IV) Cp/Cv = 9/7. Choose the correct match.

  Options

  • Option A

    A–III, B–IV, C–I, D–II

  • Option B

    A–III, B–II, C–IV, D–I

  • Option C

    A–II, B–IV, C–I, D–III

  • Option D

    A–IV, B–II, C–III, D–I

  Check answerShow answer

  JEE Mains 2025 7 April Morning Shift

  Open question & full solution →
• NumericeasyThermodynamicsThermodynamic Processes, P-V Diagrams and Work Done

  An insulated cylinder of volume 60 cm³ is filled with a gas at 27°C and 2 atmospheric pressure. Then the gas is compressed making the final volume as 20 cm³ while allowing the temperature to rise to 77°C. The final pressure is _______ atmospheric pressure.

  Your answer

  Check answerShow answer

  JEE Mains 202622 January Evening Shift

  Open question & full solution →
• MCQmediumThermodynamicsThermodynamic Processes, P-V Diagrams and Work Done

  In an Isothermal change, the change in pressure and volume of a gas can be represented for three different temperature; T₃ > T₂ > T₁ as : Image

  Options

  • Option A

    
  • Option B

    
  • Option C

    
  • Option D

    

  Check answerShow answer

  JEE Mains24 January 2023Shift 2Evening Shift

  Open question & full solution →
• MCQmediumThermodynamicsThermodynamic Processes, P-V Diagrams and Work Done

  If three moles of monoatomic gas (γ = 5/3) is mixed with two moles of a diatomic gas (γ = 7/5), the value of adiabatic exponent γ for the mixture is:

  Options

  • Option A

    1.75

  • Option B

    1.40

  • Option C

    1.52

  • Option D

    1.35

  Check answerShow answer

  JEE Mains 2024 30 Jan Evening Shift

  Open question & full solution →
• MCQmediumThermodynamicsThermodynamic Processes, P-V Diagrams and Work Done

  The internal energy of a monoatomic gas is 3nRT. One mole of helium is kept in a cylinder having internal cross section area of 17 cm² and fitted with a light movable frictionless piston. The gas is heated slowly by suppling 126 J heat. If the temperature rises by 4 °C, then the piston will move______cm.

  (atmospheric pressure = 10⁵ Pa)

  Options

  • Option A

    14.5

  • Option B

    1.55

  • Option C

    15.5

  • Option D

    1.45

  Check answerShow answer

  JEE Mains 202623 January Evening Shift

  Open question & full solution →
• NumericmediumThermodynamicsThermodynamic Processes, P-V Diagrams and Work Done

  A gas is compressed isothermally to one-third of its initial volume. The initial volume is 3 litres, and the stated bulk modulus is 3×10⁵ N·m⁻². Following the interpretation used in the given solution, take this bulk modulus as the initial isothermal bulk modulus. Find the magnitude of the work done on the gas in joules, to the nearest integer.

  Your answer

  Check answerShow answer

  JEE Mains 2026 6 April Morning Shift

  Open question & full solution →
• MCQmediumThermodynamicsThermodynamic Processes, P-V Diagrams and Work Done

  An ideal gas undergoes a process described by P = P₀[1+(V₀ / V)²]⁻¹, where P₀ and V₀ are constants. Two samples A and B, each containing two moles of gas, have initial volumes V₀ and 3V₀, respectively. They undergo the stated process and, as described in the source problem, attain the same pressure. Following the state evaluation used in the provided solution, what is T(B)-T(A)?

  Options

  • Option A

    9P₀V₀ / (8R)

  • Option B

    11P₀V₀ / (10R)

  • Option C

    7P₀V₀ / (6R)

  • Option D

    13P₀V₀ / (11R)

  Check answerShow answer

  JEE Mains 2026 4 April Morning Shift

  Open question & full solution →