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vernier callipers and screw gauge questions with solutions

Practice Unit dimension and error for JEE Main, JEE Advanced, NEET, and Classes 11–12. Attempt each question, then open it for the full solution.

Showing 1–10 of 62 questions

  • MatchdifficultUnit dimension and error

    Match each instrument specification in List I with the correct least count in List II.

    List 1

    1. 50 VSD = 48 MSD; 1 MSD = 0.5 mm

    2. 100 VSD = 97 MSD; 1 MSD = 1 mm

    3. Screw gauge: pitch = 0.4 mm, circular divisions = 80

    4. 25 VSD = 24 MSD; 1 MSD = 1 mm

    List 2

    1. 0.005 mm

    2. 0.020 mm

    3. 0.030 mm

    4. 0.040 mm

    Options

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  • Multi-correctdifficultUnit dimension and error

    A hollow tube is measured with a vernier calipers. Corrected external diameter is D and corrected internal diameter is d. Which statements are correct?

    Select all that apply

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  • IntegerdifficultUnit dimension and error

    A screw gauge advances 1.8 mm in 6 complete rotations and has 60 circular divisions. Enter the least count in micrometres.

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  • MCQdifficultUnit dimension and error

    A direct vernier is constructed such that 50 vernier scale divisions are equal to 48 main scale divisions. One main scale division is 0.50 mm. A rod gives a main scale reading of 18.00 mm and the 37th vernier division coincides with a main-scale mark. If the positive zero error is +0.06 mm, the corrected diameter of the rod is:

    Options

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  • MCQeasyUnit dimension and error

    A vernier has 10 vernier divisions equal to 9 main-scale divisions. If 1 MSD = 1 mm, its least count is:

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  • IntegerdifficultUnit dimension and error

    A spherical ball has corrected diameter 2.00 cm. Taking π = 3, enter its volume in cm³ multiplied by 10.

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  • MCQeasyUnit dimension and error

    In a screw gauge, when the two studs are in contact, the main-scale reference line coincides with the 5th division of the circular scale. The circular scale has 100 divisions and the pitch is 0.1 mm. While measuring the diameter of a sphere, the main-scale reading is 5 mm and the 50th circular-scale division coincides with the reference line. What is the corrected diameter of the sphere?

    Options

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  • A/ReasyUnit dimension and error

    Given below are two statements : one is labelled as Assertion(A) and the other is labelled as Reason (R). In the light of the above statements, choose the correct answer from the options given below :

    Assertion

    Assertion (A) : In Vernier calliper if positive zero error exists, then while taking measurements, the reading taken will be more than the actual reading.

    Reason

    Reason (R) : The zero error in Vernier Calliper might have happened due to manufacturing defect or due to rough handling.

    Options

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  • MCQdifficultUnit dimension and error

    A hollow metal sphere has corrected external diameter 30.40 mm and corrected internal diameter 26.80 mm. Its metal volume is closest to:

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  • MCQeasyUnit dimension and error

    10 divisions on the main scale of a Vernier caliper coincide with 11 divisions on the Vernier scale. If each division on the main scale is of 5 units, the least count of the instrument is:

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    JEE Mains 2024 01 Feb Morning Shift

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