A ball is projected vertically upward from the ground with an initial speed of 30 m/s. Neglect air resistance and take g = 10 m/ $s^2.$ The total distance travelled by the ball during the first 4 s after projection is:
Options

Question

A ball is projected vertically upward from the ground with an initial speed of 30 m/s. Neglect air resistance and take g = 10 m/ $s^2.$ The total distance travelled by the ball during the first 4 s after projection is:

Options

G1 Physics · Accepted Answer

Time to reach the highest point is t = u/g = 30/10 = 3 s. Maximum height = u 2 / ( 2 g ) u^2/(2g) u 2 / ( 2 g ) = 900/20 = 45 m. During the next 1 s, the ball falls a distance (1/2)g(1)^2 = 5 m. Total distance in 4 s = 45 + 5 = 50 m. Hence, option C is correct.

A ball is projected vertically upward from the ground with an initial speed of 30 m/s. Neglect air resistance and take g = 10 m/ s 2 . s^2. s 2 . The total distance travelled by the ball during the first 4 s after projection is: