A particle starts from rest and moves along a straight line with constant acceleration. It covers a total distance S in time T. The distance covered by the particle during the second half of the total time, i. e. from t = T/2 to t = T, is:
Options

Question

A particle starts from rest and moves along a straight line with constant acceleration. It covers a total distance S in time T. The distance covered by the particle during the second half of the total time, i. e. from t = T/2 to t = T, is:

Options

G1 Physics · Accepted Answer

Since the particle starts from rest, S = (1/2)aT^2. Distance covered in the first half of time is S1 = (1/2)a(T/2)^2 = S/4. Therefore distance during the second half of time = S - S/4 = 3S/4. Hence option C is correct.

A particle starts from rest and moves along a straight line with constant acceleration. It covers a total distance S in time T. The distance covered by the particle during the second half of the total time, i.e. from t = T/2 to t = T, is: