At a certain point during the upward motion of a projectile, its speed is 15 m/s and its velocity makes an angle 53° above the horizontal. Take sin53° = 4/5, cos53° = 3/5 and g = 10 m/s². The additional height gained by the projectile before reaching its highest point is:
Options

Question

At a certain point during the upward motion of a projectile, its speed is 15 m/s and its velocity makes an angle 53° above the horizontal. Take sin53° = 4/5, cos53° = 3/5 and g = 10 m/s². The additional height gained by the projectile before reaching its highest point is:

Options

G1 Physics · Accepted Answer

At the given point, the vertical component of velocity is vᵧ = 15sin53° = 15×4/5 = 12 m/s. At the highest point vᵧ becomes zero. Using 0 = 12² - 2gΔh gives Δh = 144/(20) = 7.2 m. Therefore option C is correct.