A uniformly charged thin hemispherical shell of radius R occupies x ≥ 0, with its equatorial plane at x = 0. At the point P(x,0,0), 0

Question

A uniformly charged thin hemispherical shell of radius R occupies x ≥ 0, with its equatorial plane at x = 0. At the point P(x,0,0), 0 < x < R,the electric field is $\vec{E}$ .What is the electric field at the mirror point Q(-x,0,0)?

Options

G1 Physics · Accepted Answer

Reflect the charged upper hemisphere across the equatorial plane to obtain the complementary lower hemisphere. By reflection symmetry, the field of the lower hemisphere at Q is the reflected field of the upper hemisphere at P. Since the field on the symmetry axis is axial, this reflection changes its sign. But the full spherical shell (upper + lower hemispheres) has zero field at every internal point. Therefore at Q, E⃗_upper(Q) = -E⃗_lower(Q). Combining the two relations gives E⃗_upper(Q) = E⃗…

A uniformly charged thin hemispherical shell of radius R occupies x ≥ 0, with its equatorial plane at x = 0. At the point P(x,0,0), 0 &lt; x &lt; R,the electric field is E ⃗ \vec{E} E .What is the electric field at the mirror point Q(-x,0,0)?

A uniformly charged thin hemispherical shell of radius R occupies x ≥ 0, with its equatorial plane at x = 0. At the point P(x,0,0), 0 < x < R,the electric field is E ⃗ \vec{E} E .What is the electric field at the mirror point Q(-x,0,0)?