A spherically symmetric charge distribution produces the radial electric field $\vec{E}$ = (a/r²) $e^(-r/k)$ r̂,
where a and k are positive constants.The point charge q₀ located at the origin is:
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Question

A spherically symmetric charge distribution produces the radial electric field $\vec{E}$ = (a/r²) $e^(-r/k)$ r̂,

where a and k are positive constants.The point charge q₀ located at the origin is:

Options

G1 Physics · Accepted Answer

For a spherical Gaussian surface, Q e n c ( r ) Q_enc(r) Q e ​ n c ( r ) = ε₀E(4πr²) = 4πε₀a e ( − r / k ) . e^(-r/k). e ( − r / k ) . Taking r→0⁺, q₀ = lim Q e n c ( r ) Q_enc(r) Q e ​ n c ( r ) = 4πε₀a.

A spherically symmetric charge distribution produces the radial electric field E ⃗ \vec{E} E = (a/r²) e ( − r / k ) e^(-r/k) e ( − r / k ) r̂, where a and k are positive constants.The point charge q₀ located at the origin is: