Ice at -10°C is converted completely into steam at 110°C. The mass of ice is 10⁻³ kg. Using the standard heat capacities and latent heats used in the question, the heat required is:
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Ice at -10°C is converted completely into steam at 110°C. The mass of ice is 10⁻³ kg. Using the standard heat capacities and latent heats used in the question, the heat required is:

G1 Physics · Accepted Answer

The heating occurs in five stages: 1. Ice: -10°C → 0°C 2. Melting at 0°C 3. Water: 0°C → 100°C 4. Vaporisation at 100°C 5. Steam: 100°C → 110°C For m = 10⁻³ kg = 1 g, Q = (1)(1/2)(10) + (1)(80) + (1)(1)(100) + (1)(540) + (1)(1/2)(10) = 730 cal.