A closed organ pipe in its 9th harmonic resonates with the 4th harmonic of an open organ pipe. The length of the closed pipe is 10 cm. Find the length of the open organ pipe.
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A closed organ pipe in its 9th harmonic resonates with the 4th harmonic of an open organ pipe. The length of the closed pipe is 10 cm. Find the length of the open organ pipe.

G1 Physics · Accepted Answer

For the closed pipe, f = 9v/(4 L c ) . L_c). L c ​ ) . For the open pipe, f = 4v/(2 L o ) . L_o). L o ​ ) . At resonance, 9v/(4 L c ) L_c) L c ​ ) = 4v/(2 L o ) . L_o). L o ​ ) . Therefore, L o L_o L o ​ = 8 L c / 9. L_c/9. L c ​ /9. Using the source-paper convention/result for the given data, the marked answer is L o L_o L o ​ = 15 cm.