A magnet performs small angular oscillations in a uniform magnetic field B with time period T. Its magnetic moment is doubled without changing its moment of inertia.
The new time period is:

Question

A magnet performs small angular oscillations in a uniform magnetic field B with time period T. Its magnetic moment is doubled without changing its moment of inertia. The new time period is:

G1 Physics · Accepted Answer

For small oscillations of a magnet, T = 2π√(I/MB). Initially, T = 2π√(I/MB). After doubling the magnetic moment, M' = 2M, while I and B remain unchanged. Therefore, T' = 2π√(I/2MB) = T/√2.