Above its Curie temperature, a ferromagnetic material approximately obeys the Curie-Weiss law χ=C/(T- $T_C).$ If T₁=2 $T_C$ and T₂=4 $T_C,$ then χ(T₁)/χ(T₂) is:
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Above its Curie temperature, a ferromagnetic material approximately obeys the Curie-Weiss law χ=C/(T−T_C). If T₁=2T_C and T₂=4T_C, then χ(T₁)/χ(T₂) is:

G1 Physics · Accepted Answer

Curie-Weiss law gives χ(T) = C/(T−T_C). At T₁=2T_C, χ₁ = C/(2T_C−T_C) = C/T_C. At T₂=4T_C, χ₂ = C/(4T_C−T_C) = C/(3T_C). Therefore, χ₁/χ₂ = (C/T_C)/(C/3T_C) = 3.