A projectile is fired with speed 20 m/s at an angle 60° with the horizontal. The speed at the highest point of its trajectory is:

Question

G1 Physics · Accepted Answer

At the highest point the vertical velocity is zero and horizontal velocity remains u cosθ. Thus v H = 20 c o s 60 ° = 10 v_H=20cos60°=10 v H ​ = 20 cos 60° = 10 m/s.