Two objects are at equal distances from opposite surfaces of a transparent sphere of radius R and re $fractive$ index μ, such that the image of one object is formed on the other. The object distance from the surface is:
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Question

Two objects are at equal distances from opposite surfaces of a transparent sphere of radius R and re $fractive$ index μ, such that the image of one object is formed on the other. The object distance from the surface is:

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G1 Physics · Accepted Answer

After re \fraction \fraction \fraction at the first surface, the ray must emerge inside the sphere parallel to the line joining the objects, so v=∞ for the first surface. Using μ₂/v-μ₁/u=(μ₂-μ₁)/R with μ₁=1, μ₂=μ gives |u|=R/(μ-1).

Two objects are at equal distances from opposite surfaces of a transparent sphere of radius R and re \fractive \fractive \fractive index μ, such that the image of one object is formed on the other. The object distance from the surface is: