For an ideal monoatomic gas undergoing an isobaric process, the ratio ΔQ/ΔU is:
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Question

For an ideal monoatomic gas undergoing an isobaric process, the ratio ΔQ/ΔU is:

G1 Physics · Accepted Answer

For an isobaric process, ΔQ=n C p Δ T C_pΔT C p ​ Δ T and ΔU=n C v Δ T . C_vΔT. C v ​ Δ T . Therefore ΔQ/ΔU= C p / C v = γ = 5 / 3 C_p/C_v=γ=5/3 C p ​ / C v ​ = γ = 5/3 for a monoatomic ideal gas.