A wire of total resistance 9 Ω is bent into an equilateral triangle. The equivalent resistance between any two vertices is:

Question

G1 Physics · Accepted Answer

Each side has resistance 9/3=3 Ω. Between two vertices, one path is 3 Ω and the other path is 3+3=6 Ω. Thus R e q = 3 ∣ ∣ 6 = ( 3 × 6 ) / ( 3 + 6 ) = 2 R_eq=3||6=(3×6)/(3+6)=2 R e ​ q = 3∣∣6 = ( 3 × 6 ) / ( 3 + 6 ) = 2 Ω.