Work required to break a liquid drop of radius R into 27 equal drops is 10 J. The work required to break the same drop into 64 equal drops is:

Question

G1 Physics · Accepted Answer

For n equal drops, each radius is R/ n ( 1 / 3 ) , n^(1/3), n ( 1/3 ) , so final area=4πR² n ( 1 / 3 ) . n^(1/3). n ( 1/3 ) . Increase in area ∝ n ( 1 / 3 ) − 1. n^(1/3)-1. n ( 1/3 ) − 1. Thus W₆₄/W₂₇=(4-1)/(3-1)=3/2. Therefore W₆₄=(3/2)×10=15 J.