In YDSE, the 10th bright fringe is 10 mm from the central maximum for wavelength 600 nm. For wavelength 660 nm, the distance of the 10th bright fringe from the central maximum is:
Physics · Wave Optics · young's dubble slit experiments
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Question

In YDSE, the 10th bright fringe is 10 mm from the central maximum for wavelength 600 nm. For wavelength 660 nm, the distance of the 10th bright fringe from the central maximum is:

G1 Physics · Accepted Answer

For fixed D,d and fringe order n, y n = n λ D / d , y_n=nλD/d, y n ​ = nλ D / d , so y∝λ. Therefore y₂=10×(660/600)=11 mm.