A particle moves in a vertical circle of radius R and has speed n√(gR) at the topmost point. Find K $E_bottom/KE_top.$
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A particle moves in a vertical circle of radius R and has speed n√(gR) at the topmost point. Find K E b o t t o m / K E t o p . E_bottom/KE_top. E b ​ o tt o m / K E t ​ o p .

G1 Physics · Accepted Answer

Using energy conservation from top to bottom, v b o t t o m 2 = v t o p 2 + 4 g R = ( n 2 + 4 ) g R . v_bottom²=v_top²+4gR=(n²+4)gR. v b ​ o tt o m 2 = v t ​ o p 2 + 4 g R = ( n 2 + 4 ) g R . Since kinetic energy is proportional to v², K E b o t t o m / K E t o p = ( n 2 + 4 ) / n 2 . E_bottom/KE_top=(n²+4)/n². E b ​ o tt o m / K E t ​ o p = ( n 2 + 4 ) / n 2 .

A particle moves in a vertical circle of radius R and has speed n√(gR) at the topmost point. Find K E b o t t o m / K E t o p . E_bottom/KE_top. E b ​ o tt o m / K E t ​ o p .

A particle moves in a vertical circle of radius R and has speed n√(gR) at the topmost point. Find K E b o t t o m / K E t o p . E_bottom/KE_top. E b o tt o m / K E t o p .