A particle moves from x = 0 to x = 4 m under the force F(x) = 12 - 6x N. Total work done by this force is:
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Question

A particle moves from x = 0 to x = 4 m under the force F(x) = 12 − 6x N. Total work done by this force is:

G1 Physics · Accepted Answer

W = ∫₀⁴ (12 − 6x) dx = [12x − 3x²]₀⁴ = 48 − 48 = 0. The force changes sign, so positive and negative contributions cancel.