A particle moves along the x-axis in a potential energy field U(x) = 2x³ - 9x² + 12x J. At x = 2 m, the force on the particle is:
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A particle moves along the x-axis in a potential energy field U(x) = 2x³ − 9x² + 12x J. At x = 2 m, the force on the particle is:

G1 Physics · Accepted Answer

F = −dU/dx = −(6x² − 18x + 12). At x = 2 m, F = −(24 − 36 + 12) = 0.