Two particles of masses m and 2m move in a plane with velocities v₁ = (3t², 4t) m/s and v₂ = (6t, −2t²) m/s. At t = 1 s, the acceleration of the centre of mass is a(CM) = (A, B) m/s². If 3(A+B) = N, find N.
Physics · Center of maas , Momentum and Collision · velocity and acceleration of center of mass,newton second law for system
Two particles of masses m and 2m move in a plane with velocities v₁ = (3t², 4t) m/s and v₂ = (6t, -2t²) m/s. At t = 1 s, the acceleration of the centre of mass is a(CM) = (A, B) m/s². If 3(A+B) = N, find N.