An electric bulb rated 100 W, 220 V is connected to an AC source of rms voltage 220 V. According to the source paper, the peak value of current through the bulb is:
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Question

An electric bulb rated 100 W, 220 V is connected to an AC source of rms voltage 220 V. According to the source paper, the peak value of current through the bulb is:

G1 Physics · Accepted Answer

The source paper uses I = P/V = 100/220 ≈ 0.45 A and marks option C. This value is the RMS current because the given voltage 220 V is an RMS value. If the phrase 'peak current' is interpreted literally, then I p e a k I_peak I p ​ e ak = √2 I r m s I_rms I r ​ m s ≈ 1.414×0.45 ≈ 0.64 A, which corresponds to option D. To preserve the original paper exactly, the Correct Answer field is kept as option C, matching the printed source key.