Match List-I with List-II. List-I: (A) Isobaric, (B) Isochoric, (C) Adiabatic, (D) Isothermal. List-II: (I) ΔQ = ΔW, (II) ΔQ = ΔU, (III) ΔQ = 0, (IV) ΔQ = ΔU + PΔV. Choose the correct match.
Options

Question

Match List-I with List-II. List-I: (A) Isobaric, (B) Isochoric, (C) Adiabatic, (D) Isothermal. List-II: (I) ΔQ = ΔW, (II) ΔQ = ΔU, (III) ΔQ = 0, (IV) ΔQ = ΔU + PΔV. Choose the correct match.

G1 Physics · Accepted Answer

Using the first law of thermodynamics with ΔW as work done by the system: ΔQ = ΔU + ΔW. For an isobaric process, ΔW = PΔV, so ΔQ = ΔU + PΔV. Thus A–IV. For an isochoric process, ΔV = 0 ⇒ ΔW = 0, so ΔQ = ΔU. Thus B–II. For an adiabatic process, ΔQ = 0. Thus C–III. For an isothermal process of an ideal gas, ΔU = 0, so ΔQ = ΔW. Thus D–I. Therefore A–IV, B–II, C–III, D–I. Correct option: B.