A slow neutron is absorbed by a uranium-235 nucleus and fission occurs according to ²³⁵₉₂U + ¹₀n → ¹⁴¹₅₆Ba + ⁹²₃₆Kr + x(¹₀n). Assuming no other massive particles are produced, how many neutrons are emitted in this fission event?
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Question

A slow neutron is absorbed by a uranium-235 nucleus and fission occurs according to ²³⁵₉₂U + ¹₀n → ¹⁴¹₅₆Ba + ⁹²₃₆Kr + x(¹₀n). Assuming no other massive particles are produced, how many neutrons are emitted in this fission event?

Options

G1 Physics · Accepted Answer

Apply conservation of mass number. Initial mass number: 235+1 = 236. Known final mass number: 141+92 = 233. If x neutrons are emitted, 236 = 233+x. Therefore, x = 3. Atomic number is also conserved: 56+36 = 92. Correct option: C.