For a particular nuclear fission event, the total rest mass of the products is smaller than the total initial rest mass by 0.215 u. Take 1 u·c² = 930 MeV. If the energy released is approximately N MeV, find N.
Physics · Nuclear physics · nuclear fission and fusion ,nuclear reactor
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Question

For a particular nuclear fission event, the total rest mass of the products is smaller than the total initial rest mass by 0.215 u. Take 1 u·c² = 930 MeV. If the energy released is approximately N MeV, find N.

Physics · Nuclear physics · nuclear fission and fusion ,nuclear reactor

G1 Physics · Accepted Answer

Energy released in the fission is obtained from the mass defect: Q = Δm·c². Given, Δm = 0.215 u and 1 u·c² = 930 MeV. Therefore, Q = 0.215×930 = 199.95 MeV. This is approximately 200 MeV. Hence N = 200.