In the same simplified K-series model, if ν(Kγ) ÷ ν(Kα) = N ÷ 4, find N.

Question

G1 Physics · Accepted Answer

For Kγ radiation, the electron is treated as falling from the fourth shell to the first shell: ν(Kγ) ∝ 1−1 ÷ 4² = 1−1 ÷ 16 = 15 ÷ 16. For Kα: ν(Kα) ∝ 3 ÷ 4. Therefore, ν(Kγ) ÷ ν(Kα) = (15 ÷ 16) ÷ (3 ÷ 4) = (15 ÷ 16)×(4 ÷ 3) = 5 ÷ 4. Hence N = 5.