An electron starts from rest and is accelerated through a potential difference of 511 kV. At this energy, a relativistic momentum expression must be used. Take K = 511 keV, mₑc² = 511 keV, pc = √[K(K+2mₑc²)] and hc = 1240 eV·nm. Which value is closest to the electron's de Broglie wavelength?
Physics · Photoelectric effect and dual nature of matter · debroglie duel nature of light
An electron starts from rest and is accelerated through a potential difference of 511 kV. At this energy, a relativistic momentum expression must be used. Take K = 511 keV, mₑc² = 511 keV, pc = √[K(K+2mₑc²)] and hc = 1240 eV·nm. Which value is closest to the electron's de Broglie wavelength?
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