A mass of (7/17.13) kg of ⁷₃Li is completely converted into ⁴₂He through proton bombardment according to the reaction ⁷₃Li + ¹₁H → 2⁴₂He. The total energy released is α×10³² eV. Given: mass of ⁷₃Li = 7.0183 u, mass of ⁴₂He = 4.004 u, mass of proton = 1.008 u, 1 u = 931 MeV·c⁻², and Avogadro number = 6.0×10²³ mol⁻¹. Find the nearest integer value of α.
Physics · Nuclear physics · Nucles and its density radius and mass defect ,binding energy and its curve
A mass of (7/17.13) kg of ⁷₃Li is completely converted into ⁴₂He through proton bombardment according to the reaction ⁷₃Li + ¹₁H → 2⁴₂He. The total energy released is α×10³² eV. Given: mass of ⁷₃Li = 7.0183 u, mass of ⁴₂He = 4.004 u, mass of proton = 1.008 u, 1 u = 931 MeV·c⁻², and Avogadro number = 6.0×10²³ mol⁻¹. Find the nearest integer value of α.