A solid sphere of mass M and radius R is divided into two unequal parts. The smaller part has mass M /8 and is reshaped into a sphere of radius r. The larger part has mass 7M /8 and is reshaped into a circular disc of thickness t and radius 2R. Let I₁ be the moment of inertia of the smaller sphere about an axis through its centre, and I₂ be the moment of inertia of the disc about its diameter. Assuming the material density remains unchanged, what is I₂ / I₁?
Physics · Rotational Motion · moment of inertia and kinetic energy in pure rotation
A solid sphere of mass M and radius R is divided into two unequal parts. The smaller part has mass M /8 and is reshaped into a sphere of radius r. The larger part has mass 7M /8 and is reshaped into a circular disc of thickness t and radius 2R. Let I₁ be the moment of inertia of the smaller sphere about an axis through its centre, and I₂ be the moment of inertia of the disc about its diameter. Assuming the material density remains unchanged, what is I₂ / I₁?
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