In the capacitor network shown in the figure, C₁ = C₂ = C₃ = 1 μF and C₄ = 2 μF. What is the equivalent capacitance between terminals A and B?

Question

G1 Physics · Accepted Answer

Reading the node connections from the circuit diagram, the network can be redrawn as follows: • One 1 μF capacitor is connected directly between A and B. • Two 1 μF capacitors are connected in parallel between A and the intermediate node C. Their equivalent is C(AC) = 1+1 = 2 μF. • The 2 μF capacitor C₄ is connected between C and B. Thus the A-C equivalent of 2 μF is in series with the C-B capacitance of 2 μF: C(series) = (2×2) ÷ (2+2) = 1 μF. This series branch is in parallel with the direct 1…