In a Young's double-slit experiment, the individual intensities contributed by the two slits at a point are I and 4I. What are the maximum and minimum possible resultant intensities?
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Question

In a Young's double-slit experiment, the individual intensities contributed by the two slits at a point are I and 4I. What are the maximum and minimum possible resultant intensities?

G1 Physics · Accepted Answer

The corresponding amplitudes are √I and 2√I. Therefore, I(max) = (√I+2√I)² = 9I, and I(min) = (2√I−√I)² = I. Correct option: B.