In a Young's double-slit experiment, the individual slit intensities are I and 4I. What is the visibility of the interference fringes?
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In a Young's double-slit experiment, the individual slit intensities are I and 4I. What is the visibility of the interference fringes?

G1 Physics · Accepted Answer

Using I(max) = 9I, I(min) = I, visibility is V = (9I−I) ÷ (9I+I) = 8 ÷ 10 = 0.80. Correct option: C.