Two cars A and B each of mass 10³ kg are moving on parallel tracks separated by a distance of 10 m, in same direction with speeds 72 km/h and 36 km/h. The magnitude of angular momentum of car A with respect to car B i $s ___$ J.s.
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Question

Two cars A and B each of mass 10³ kg are moving on parallel tracks separated by a distance of 10 m, in same direction with speeds 72 km/h and 36 km/h. The magnitude of angular momentum of car A with respect to car B i $s ___$ J.s.

Options

G1 Physics · Accepted Answer

The relative speed of car A with respect to car B is vᵣₑₗ = 72 - 36 = 36 km/h. Convert to SI units: vᵣₑₗ = 36 × 5/18 = 10 m/s. The perpendicular distance from car B to the line of relative motion of car A is r⊥ = 10 m. Therefore the magnitude of angular momentum is L = m vᵣₑₗ r⊥ = 10³ × 10 × 10 = 10⁵ kg·m²/s = 10⁵ J·s. Correct option: B.

Two cars A and B each of mass 10³ kg are moving on parallel tracks separated by a distance of 10 m, in same direction with speeds 72 km/h and 36 km/h. The magnitude of angular momentum of car A with respect to car B i s ___ J.s.