The correct truth table for the given input data of the following logic gate is :

Question

G1 Physics · Accepted Answer

From the circuit: The upper branch first forms A·B, then inverts it: P = NOT(A·B). The lower OR gate gives Q = C + D. These two signals are fed to an AND gate and the result is inverted. Thus, Y = NOT[P·Q] = NOT{NOT(A·B) · (C + D)}. Using De Morgan's theorem, Y = A·B + NOT(C + D). Now evaluate the four given input sets: 1) A B C D = 1 1 0 1 A·B = 1, C + D = 1, NOT(C + D) = 0, so Y = 1. 2) 0 0 1 1 A·B = 0, C + D = 1, NOT(C + D) = 0, so Y = 0. 3) 1 0 1 0 A·B = 0, C + D = 1, NOT(C + D) = 0, so Y =…