Match List-I with List-II.
List-I (Relation)
A. ∮ $\vec{E}$ · $\vec{dl}$ = -d/dt ∫ $\vec{B}$ · $\vec{da}$
B. ∮ $\vec{B}$ · $\vec{dl}$ = μ₀[I + ε₀ dΦ(E)/dt]
C. ∮ $\vec{E}$ · $\vec{da}$ = (1/ε₀)∫ρ dv
D. ∮ $\vec{B}$ · $\vec{dl}$ = μ₀I
List-II (Law)
I. Ampere's circuital law. II. Faraday's laws of electromagnetic induction. III. Ampere-Maxwell law IV. Gauss's law of electrostatics
Choose the correct answer from the options given below :
Options

Question

Match List-I with List-II.

List-I (Relation)

A. ∮ $\vec{E}$ · $\vec{dl}$ = -d/dt ∫ $\vec{B}$ · $\vec{da}$

B. ∮ $\vec{B}$ · $\vec{dl}$ = μ₀[I + ε₀ dΦ(E)/dt]

C. ∮ $\vec{E}$ · $\vec{da}$ = (1/ε₀)∫ρ dv

D. ∮ $\vec{B}$ · $\vec{dl}$ = μ₀I

List-II (Law)

I. Ampere's circuital law. II. Faraday's laws of electromagnetic induction. III. Ampere-Maxwell law IV. Gauss's law of electrostatics

Choose the correct answer from the options given below :

Options

G1 Physics · Accepted Answer

Match each field equation with its law. A. ∮E⃗·dl⃗ = -d/dt ∫B⃗·da⃗ is Faraday's law of electromagnetic induction. Therefore, A → II. B. ∮B⃗·dl⃗ = μ₀[I + ε₀ dΦ(E)/dt] is the Ampere-Maxwell law. Therefore, B → III. C. ∮E⃗·da⃗ = (1/ε₀)∫ρ dv is Gauss's law of electrostatics. Therefore, C → IV. D. ∮B⃗·dl⃗ = μ₀I is Ampere's circuital law. Therefore, D → I. Hence the correct matching is A-II, B-III, C-IV, D-I. Correct option: B.