In hydrogen atom spectrum, (R → Rydberg's constant)
A. the maximum wavelength of the radiation of Lyman series is 4/(3R)
B. the Balmer series lies in the visible region of the spectrum
C. the minimum wavelength of the radiation of Paschen series is 9/R
D. the minimum wavelength of Lyman series is 5/(4R)
Choose the correct answer from the options given below :

Question

In hydrogen atom spectrum, (R → Rydberg's constant)

A. the maximum wavelength of the radiation of Lyman series is 4/(3R)

B. the Balmer series lies in the visible region of the spectrum

C. the minimum wavelength of the radiation of Paschen series is 9/R

D. the minimum wavelength of Lyman series is 5/(4R)

Choose the correct answer from the options given below :

G1 Physics · Accepted Answer

For the Lyman series, transitions terminate at n = 1. The maximum Lyman wavelength corresponds to the smallest energy gap: n = 2 → n = 1. Therefore, 1/λ(max,Lyman) = R[1 - 1/4] = 3R/4. Hence, λ(max,Lyman) = 4/(3R). So A is correct. The Balmer series terminates at n = 2 and its important lower members lie in the visible region. Therefore B is correct. For the Paschen-series limit, n = ∞ → n = 3. Hence, 1/λ(min,Paschen) = R/9. Therefore, λ(min,Paschen) = 9/R. So C is correct. For the Lyman-series…