A closed vessel containing oil of density 800 kg/m³ is accelerating vertically downward with acceleration 6 m/s². Two points in the oil are vertically separated by 0.50 m. Taking g = 10 m/s², what is the magnitude of the pressure difference between these points?
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Question

A closed vessel containing oil of density 800 kg/m³ is accelerating vertically downward with acceleration 6 m/s². Two points in the oil are vertically separated by 0.50 m. Taking g = 10 m/s², what is the magnitude of the pressure difference between these points?

Options

G1 Physics · Accepted Answer

When the vessel accelerates downward with acceleration a, the effective gravitational acceleration is g(eff) = g−a = 10−6 = 4 m/s². Therefore, ΔP = ρg(eff)h = 800×4×0.50 = 1600 Pa = 1.6 kPa. Correct option: A.