An open rectangular tank of length 1.2 m initially contains water to a uniform depth of 0.50 m. The tank is accelerated horizontally toward the right with 5 m/s² and no water spills. Taking g = 10 m/s², the water depth at the left wall is N cm. Find N.
Physics · Fluid Mechanics · question based on variation of pressure
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Question

An open rectangular tank of length 1.2 m initially contains water to a uniform depth of 0.50 m. The tank is accelerated horizontally toward the right with 5 m/s² and no water spills. Taking g = 10 m/s², the water depth at the left wall is N cm. Find N.

Physics · Fluid Mechanics · question based on variation of pressure

G1 Physics · Accepted Answer

The free-surface level difference is Δh = La/g = 1.2×5/10 = 0.60 m. Since no water spills and the tank cross-section is uniform, the average depth remains 0.50 m. Therefore the left-wall depth is h(left) = 0.50 + Δh/2 = 0.50+0.30 = 0.80 m = 80 cm. Hence, N = 80.