A uniform cube of side 10 cm and density 600 kg/m³ floats in water of density 1000 kg/m³. Its submerged height is N cm. Find N.

Question

G1 Physics · Accepted Answer

For a floating body, buoyant force = weight. Therefore, ρ(water)V(sub)g = ρ(block)V(total)g. Hence, V(sub)/V(total) = ρ(block)/ρ(water) = 600/1000 = 0.6. For a cube, the submerged-volume fraction equals the submerged-height fraction. Thus, h(sub) = 0.6×10 = 6 cm. Hence, N = 6.