A Pitot tube is used to measure the speed of air of density 1.2 kg/m³. The stagnation pressure measured by the Pitot opening exceeds the static pressure by 1500 Pa. Assuming incompressible ideal flow, what is the air speed?
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Question

A Pitot tube is used to measure the speed of air of density 1.2 kg/m³. The stagnation pressure measured by the Pitot opening exceeds the static pressure by 1500 Pa. Assuming incompressible ideal flow, what is the air speed?

Options

G1 Physics · Accepted Answer

At the stagnation point, the fluid speed becomes zero. Applying Bernoulli's equation between the moving air and the stagnation point, P(stagnation)−P(static) = ½ρv². Therefore, 1500 = ½×1.2×v². Hence, v² = 1500/0.6 = 2500. Thus, v = 50 m/s. Correct option: C.