The water surface in a large open tank is 10 m above the ground. One small hole is made 2 m above the ground. At what height should a second small hole be made so that the two water jets strike the ground at the same horizontal distance from the tank?
Options

Question

The water surface in a large open tank is 10 m above the ground. One small hole is made 2 m above the ground. At what height should a second small hole be made so that the two water jets strike the ground at the same horizontal distance from the tank?

Options

G1 Physics · Accepted Answer

For a hole at height y above the ground and water-surface height H, R = 2√[y(H−y)]. Two holes have the same range when y₁(H−y₁) = y₂(H−y₂). For the non-identical pair, the two heights are complementary: y₁+y₂ = H. Given, H = 10 m, y₁ = 2 m. Therefore, y₂ = 10−2 = 8 m. Correct option: D.