A wetting liquid rises through height h₀ in a capillary tube when the apparatus is stationary. The apparatus is then accelerated vertically downward with acceleration a, where a is smaller than g. What is the new capillary rise?
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Question

A wetting liquid rises through height h₀ in a capillary tube when the apparatus is stationary. The apparatus is then accelerated vertically downward with acceleration a, where a is smaller than g. What is the new capillary rise?

Options

G1 Physics · Accepted Answer

During downward acceleration, g(eff) = g−a. The capillary-rise relation becomes h = [2S cosθ] / [ρr(g−a)]. Using h₀ = [2S cosθ] / [ρrg], we obtain h = h₀g / (g−a). Because g−a is smaller than g, the capillary rise increases. Correct option: A.